Directional Sense


 
 
Concept Explanation
 

Directional Sense

DIRECTIONAL SENSE:

Introduction:

In this test, the questions consist of a sort of direction puzzle. A successive follow-up of directions is formulated and the candidate is required to ascertain the final direction or the distance between two points. The test is meant to judge the candidate,s ability to trace and follow corrrectly amd sense the directon correctly and sense the direction correctly.

The adjoining figure shows the four main directions (North N, South S, East E, West W) and four cardinal directions (North East NE, North West NW, South East SE, South West SW) to help the candidates know the directions.

image. required

 

Example 4: Kailash faces towards north.Turning to his right, he walks 25 metres. He then turns to his left and walks 30 metres. Next, he moves 25 metres to his right. He then turns to his right again and walks 55 metres. Finally, he turns to the right and moves 40 metres. In which direction is he now from his startinig point ?

(a) South-west           (b) South     (c) North-west       (d) South-east

SOlution: Kailash turns towards right from north direction. So, he walks 25 m towards east upto B, turns left and moves 30 m upto C, turns right and goes 25 m upto D. At D, he turns to right towards the south and walks 55 m upto E. Next, he again turns to right and walks 40 m upto F, whihc is his final position. F is to the South-east of A. So, he is to the south-east from his starting point. Hence, the answer is (d).

Example 6: Deepak starts walking straight towards east. After walking 75 metres, he turns to the left and walks 25 metres straight. Again he turns to the left, walks a distance of 40 metres straight, again he turns to the left and walks a distance of 25 metres. How far is he from the starting point ?

(a) 25 metres      (b) 50 metres       (c) 115 metres      (d) 140 metres     (e) None of these

Solution: (e) The movements of Deepak are as shown in fig.

Clearly, EB = DC = 40 m.

large therefore Deepak,s distance from the startinf point A

           = (AB - EB)

           = (75 - 40) m = 35 m.

Example 7: Namita walks 14 metres towards west, then turns to her right and walks 14 metres and then turns to her left and walks 10 metres. Again turning to her left she walks 14 metres. What is the shortest distance (in metres) between her starting point and the present position ?

(a) 10          (b) 24       (c) 28        (d) 38

Solution: (b) The movements of Namita are as shown in Fig. (A to B, B to C, C to D and D to E).

Clearly,Namita,s distance from his initial position = AE = (AB + BE) = (AB + CD)

              = (14 + 10) m = 24 m.

Example 8: Gopal starts from his house towards west. After walking a distance of 30 metres, he turned towards right and walked 20 metres. He then turned left and moving a distance of 10 metres, turned to his left again and walked 40 metres. He now turns to the left and walk 5 metres. Finally he turns to his left. In which direction is he walking now ?

(a) North          (b) South       (c) East       (d) South-west      (e) West

Solution: (a) The movements of Gopal are as shown in Fig From A to G.

Clearly, Gopal is finally walking in the direction FG i..e, North.

 

Example 10: I am facing South. I turn right and walk 20 m. Then I turn right again and walk 10 m. Then I turn left and walk 10 m and then turning right walk 20 m. Then I turn right again and walk 60 m. In which direction am I from the starting point ?

(a) North         (b) North-west       (c) East       (d) North-east

Solution: (d) The movements of the person are from A to F, as shown in Fig. Clearly, the final position is F which is to the North-east of the starting point A.

Example 11: From his house, Lokesh went 15 kms to the North. Then he turned West and covered 10 kms. Then, he turned South and covered 5 kms. FInally, turning to East, he covered 10 kms. In which direction is he from his house ?

(a) East       (b) West        (c) North         (d) South

Solution: (c) The movements of Lokesh are as shown in fig. (A to B, B to C, C to D and D to E).

Clearly,his final position is E which is to the North of his house at A.

Example 12: A child is looking for his father. He went 90 metres in the East before turning to his right. He went 20 metres before turning to his right again to look for his fatherat his uncle,s place 30 metres from this point. His father was not there. From here he went 100 metres to the North before meeting his father in a street. How far dud the son meet his father from the starting point ?

(a) 80 metres      (b) 100 metres       (c) 140 metres      (d) 260 metres

Solution: (b) The movements of the child from A to E are as shown in fig.

Clearly, the child meets his father at E.

Now, AF = (AB - FB)

             = (AB - DC) = (90 - 30) m = 60 m.

EF = (DE - DF) = (DE - BC)

   = (100 - 20) m = 80m.

large therefore Required distance

large =AE=sqrt{AF^{2}+EF^{2}}=sqrt{(60)^{2}+(80)^{2}}

large =sqrt{3600+6400}=sqrt{10000}=100m.

Example 13: Two buses start from the opposite points of a main road, 150 kms apart. The first bus runs for 25 kms and takes a right turn and then runs for 15 kms. It then turns left and runs for another 25 kms and takes the direction back to reach the main road. In the meantime, due to a minor breakdown, the other bus has run only 35 kms along the main road.What would be the distance between the two buses at this point?

(a) 65 kms       (b) 75 kms     (c) 80 kms      (d) 85 kms

Solution: (a) Let X and Y be two buses

Bus X travels along the path PA, AB, BC, CD.

Now, AD = BC = 25 km.

So, PD = PA + AD = 50 km.

Bus, Y travels 35 km upto E.

large therefore Distance between two buses = PQ - (PD + QE) = (150 - (50 + 35) km = 65 km.

Example 14: Of the five villages P, Q, R, S and T situated close to each other, P is to the west of Q, R is to the south of P, T is to the north of Q and S is to the east of T. Then, R is in which directon with respect to S ?

(a) North -west       (b) South-east   (c) South-west    (d) Data inadequate    (e) None of these

Solution: (c) Clearly, the location of villages according to the given directions is as shown.

So, R lies to the south-west of S.

Example 15: Of the six members of a panel sitting in a row, A is to the left of D, but on the right of E. C is on the right of X, but is on the left of B who is to the left of F. Which two members are sitting right in the middle ?

(a) A and C          (b) C and B         (c) D and B       (d) D and C

Solution: A is the left of D means AD. Ais to right of E means EA. So, the sequence is EAD.C is tothe left of B means CB. B is to the left of F means BF. So the sequence is XCBF.Thus, the re are two possible arrangements- EADXCBF.and XCBFEAD. In the first arrangement, the two members in the middle are D and C. In the second arrangement, the two members in the middle are B and E. So, from amongst the choices, D and C is the answer.

Study the information given below carefully and answer the questions that follow:

A, B, C, D, E, F, G, H and I are nine houses. C is 2 km east of B. A is 1 km north of B and H is 2 km south of A. G is 1 km west of H while D is 3 km east of G and F is 2 km northof G. I is situated just in middle of B and C while E is just in middle of H and D.

1. Distance between E and G is

(a) 1 km        (b) 1.5 km        (c) 2 km        (d)

Solution: (c) SInce E lies in middle of H and D, so HE = ED.

But HD = 2km.So, HE = ED = 1 km.

large therefore  Required distance = GE = GH + HE

                                = (1 + 1) km = 2 km

2. Distance between E and I is

(a) 1 km       (b) 2 km        (c) 3 km      (d) 4 km

Solution: (a) I lies in middle of B and C. So, BI = IC.

But BC = 2 km . So, BI = IC = 1km.

So, I lies directly above E.

large therefore  Required distance = EI = HB = 1 km.

3. Distance between A and F is

(a) 1 km            (b) 1.41 km       (c) 2 km          (d) 3 km

Solution: (a) Since GF = AH = 2km, so F and A lie in the same line.

large therefore  Required distance = AF = GH = 1 km.

Example 16: From the position in original figure, C and A move diagonally to opposite corners and then oneside each clockwise and anti-clockwise respectively. B ad D move two sides each clockwise and anti-clockwise respectively. Where is A now ?

(a) At the north-west corner     (b) At the north-east corner      (c) At the south-east corner

(d) At the south-west corner    (e) Midway between original positions of B and D.

Solution: (d) The movements of A, C, B and D are shown in figures (i), (ii), (iii) and (iv) respectively. The final configuration is shown in(v). Comparing (v) with the given diagram. A is in the South-west corner.

Sample Questions
(More Questions for each concept available in Login)
Question : 1

Maya starts at point T and walks straight to a point which is 4 ft away. She turns left at 90^0 and walks to W which is 4 ft away, trns 90^0  right and goes to 3 ft to P, turns  90^0 right and walks 1 ft to Q, turns left at 90^0 and goes to V , which is 1 ft away and once again trns 90^0 right and goes to R, 3 ft away. What is the distance between T and R?

Right Option : D
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Question : 2

A villager went to meet his uncle in another village situated 5 km away in the north-east direction of his own village. From there, he came to meet his father-in-law living in a village situated 4 km in the south of his uncle's village. How far away and in what direction is he now?

Right Option : B
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Question : 3

Ram is facing south. He turns right and walks 40 m.Then he turns right again and walks 40m. finally, he turns right again and walks 80 m.in which direction is he from the starting point?

Right Option : C
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